If the answer to this question is five, what’s the question?
Start by sending two wolves across the river, resulting in:
You can then send one wolf back to the left bank:
Now, send the remaining two wolves to the right bank, which results in having all of the chickens on one side and all of the wolves on the other:
Send one wolf back, then move two chickens to the right:
The next move (the sixth one) is to send a wolf and a chicken back, resulting in:
(This could also be achieved simply by sending a wolf and a chicken across in the first place, but the raft would be on the right bank, instead of on the left, as it is now.)
Next, move the two remaining chickens across:
The remaining wolf can take the raft back across for the others:
Now, it’s a simple matter to send two wolves across, send one back, and finally sending the other two wolves across in three more moves, resulting in eleven moves and:
Your first instinct says,”If a dog-and-a-half eats a pound and a half in a day and a half, that means that a dog eats a pound in a day, and so a dog eats six pounds in six days, right?”
Actually, it means that a dog eats a pound in a day-and-a-half, so a dog really eats four pounds in six days.
70/7 in words is seventy/seven, which simplifies to ‘ty’. If A=1, B=2 etc., t x y = 20 x 25 = 500.
This is a puzzle I remember from a puzzle book I once read, and it is my favourite type of puzzle: simple at first glance, but then you find that that’s not all.
If a dog-and-a-half eats a pound and a half in a day and a half, then how much can one dog eat in six days?